Sept. 21 (Bloomberg) -- South Africa beat Zimbabwe by 10 wickets to advance to the next stage of cricket’s ICC World Twenty20 competition. The result also sends host Sri Lanka through and eliminates Zimbabwe.
Man of the match Jacques Kallis took 4-15 last night in Hambantota as Zimbabwe ended on 93-8 after being put in to bat.
Craig Ervine, with 37 runs, and Stuart Matsikenyeri, on 11, were the only Zimbabwe batsmen to reach double figures in the Group C game. Morne Morkel took 2-16 and Dale Steyn 1-9, while wicketkeeper-captain AB de Villiers took four catches.
South Africa finished on 94-0 in 12.4 overs, Richard Levi scoring 50 and Hashim Amla 32.
“I backed our pace bowlers to do well on this track and Dale and Morne set the trend for us to follow,” De Villiers said at the post-match presentation. “We’ve improved a lot in these conditions and we’ve got a balanced bowling attack, so we can’t wait to take on what comes at us.”
Sri Lanka and South Africa have two points each in Group C, while Zimbabwe finishes with none. South Africa and Sri Lanka meet in Hambantota on Sept. 22 in the final group match.
Today, defending champion England plays its first game in Group A against Afghanistan in Colombo, while Bangladesh and New Zealand meet in Group D in Pallekele.
The top two in each of the four groups go through to a Super Eight stage, from which the top two teams in each pool advance to the semifinals. The final is in Colombo on Oct. 7.
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